Question

a particle is moving in a straight line with constant acceleration of 1.5 m/s2. Initially its velocity in 4.5 m/s2. Fine the velocity of the particle​

Answer 1

Velocity of the particle after 1 second :

• Acceleration (a) = 1.5 m/s²
• Initial velocity (u) = 4.5 m/s
• Time taken (t) = 1 second

★ v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

→ v = 4.5 + 1.5(1) m/s

→ v = 4.5 + 1.5 m/s

→ v = 6 m/s

Therefore, the velocity after 1 second is 6 m/s.

$\underline{ \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}$

Velocity of the particle after 3 seconds :

• Acceleration (a) = 1.5 m/s²
• Initial velocity (u) = 4.5 m/s
• Time taken (t) = 3 seconds

★ v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

→ v = 4.5 + 1.5(3) m/s

→ v = 4.5 + 4.5 m/s

→ v = 9 m/s

Therefore, the velocity after 3 seconds is 9 m/s.

$\underline{ \qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}$

Velocity of the particle after t seconds :

• Acceleration (a) = 1.5 m/s²
• Initial velocity (u) = 4.5 m/s
• Time taken (t) = t seconds

★ v = u + at

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time

→ v = 4.5 + 1.5(t) m/s

→ v = 4.5 + 1.5t m/s

Therefore, the velocity after t second is (4.5 + 1.5t) m/s.