Question

A particle is moving in a straight line with initial velocity of 200 ms'acceleration of the particle
is given by a = 3t+ - 21. Find velocity of the particle at 10 second.
(A) 1100ms
(B) 300ms (C900m
(D) 100ms
Twoh​

Answer 1

Answer:

the ans correct is option D

Explanation:

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Answer 2

Answer:(B)300ms

u=200ms'

a=3t+(-21)

v=?

t=10 seconds

a=u-v/t

-at-u=v

-(3t-21)10-200

= -30t+210-200

= -30t+10

= -300+10

= -290

So , ans. is 290(approx to 300)