Question

A particle is moving in a straight line with initial velocity 'u' and uniform acceleration 'a' if the sum of the distances travelled in t th and (t+1)th second is 100cm then it's velocity after 't' seconds in cm/s is ​

Answer 1

Answer:

hii mate hope this answer helps you---

Explanation:

given, initial velocity(u)=u

uniform acceleration (a)=a

sum of distance travelled in t th and (t+1)th sec =100

see there is a formula for calculating for calculating the distance of a uniformly accelerating body at nth second.

That is , s t=u+a/2 (2n-1).

where u=uniform velocity and a=acceleration ok.

Now,

given that sum of distances travelled in t th and (t+1)th sec=100.

---->>> st+st+1=100----(1)

s th= u+a/2 ×2(t-1)

s(t+1)th= u+a/2× 2(t+1)-1=u+a/2× 2t+1.

substitute this values in 1

u+a/2×(2t-1)+ u+a/2×(2t+1)=100

implies,u+at-a/2+u +at+a/2=100

that implies, 2u +2at=100

----->>u+at=100/2=50

now from the equation , v=u+at

v=50cm/s

therefore, the velocity of the particle after tth second will be 50 cm/s.

hope this helps you

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