A particle is moving in a straight line with its position is given by x = (8.50 m/s2)t2 + 6.0 m. Calculate :(a) The instantaneous velocity at t1 = 3.00 s and t2 = 5.00 s. (b) Its average acceleration during the interval from t1 = 3.00 s to t2 = 5.00 s. (c) Its instantaneous acceleration as a function of time.
Answers
Answered by
0
Answer:
The instantaneous velocity of an object is the velocity at a certain instant of time. Velocity is the change in position divided by the change in time, and the instantaneous velocity is the limit of velocity as the change in time approaches zero. This is equivalent to the derivative of position with respect to time.
Similar questions