Physics, asked by XxRishabhRathorexX, 8 days ago

A particle is moving in a three-dimensional potential V(x, y,z)=--mo (2x² + y2 + 4zº). 2 If the mass of the particle is m, then what is the energy of the particle in the lowest quantum State?​​

Answers

Answered by AnirudhTyagi55
3

Answer:

This your answer beta ji

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Answered by ImpressAgreeable4985
0

Explanation:

HERE'S YOUR ANSWER

85. Fig. shows the displacement of a particle moving

along x-axis as a function of time. The acceleration

of the particle is zero in the region :

of the

1th and

displacement

timeparticle is moving in a three dimensions potential V(x)=1/2mw^2(2x^2+y^2+4z^2). if the mass of the particle is m then what is the energy of the particle in the lowest quantum

(a) AB

HOPE IT HELPS YOU MARK IT BRAINLIEST PLEASE

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