a particle is moving in a three-dimensional potential V(x,y,z) = (1/2)mw²(2x²+y²+4z²). If the mass of the particle is m, then what is the energy of the particle in the lowest state?
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Answer:
this is the answer
Explanation:
Correct option is
A
−2K(x
i
^
+y
j
^
+z
k
^
)
The relation between potential energy and force is given by,
F
=−(
∂x
∂U
i
^
+
∂x
∂U
j
^
+
∂x
∂U
k
^
)
Putting the value of U in the above equation will get,
F
=−2K(x
i
^
+y
j
^
+
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