Question

a particle is moving in a three dimensions potential V(x)=1/2mw^2(2x^2+y^2+4z^2). if the mass of the particle is m then what is the energy of the particle in the lowest quantum state ?

Answer 1

Explanation:

HERE'S YOUR ANSWER

85. Fig. shows the displacement of a particle moving

along x-axis as a function of time. The acceleration

of the particle is zero in the region :

of the

1th and

displacement

timeparticle is moving in a three dimensions potential V(x)=1/2mw^2(2x^2+y^2+4z^2). if the mass of the particle is m then what is the energy of the particle in the lowest quantum

(a) AB

HOPE IT HELPS YOU MARK IT BRAINLIEST PLEASE

Answer 2

Answer:

no

Explanation:

because options is

1 √7/2hw

2. [3+√2/2]hw

3. [3/2(3+√2)]hw

4. 3/2hw