Question

A particle is moving in circles of diameter 30 m find distance and displacement for 1,1.5,2 and 2.5 round

Answer 1

Explanation:

distance for 1 rnd=30π

disp=0

for 1.5, dist=45π

disp=30

for 2, dist=60π

disp=0

for 2.5, dist=75π

disp=0

Answer 2

Answer:

Explanation:

SEE HERE

DIAMETER=30M. (GIVEN)

THEN,RADIUS SHOULD BE 1/2 OF D

=>1/2 OF 30M =15M

DISTANCE OF THE CIRCLE MEANS THE PERIMETER OF THE CIRCLE,SO

=>PERIMETER OF CIRCLE=2πR

DIST. FOR 1 ROUND=2πR×NO. OF ROUND

=>DIST. TRAVELLED FOR 1 ROUND = 2×3.14×15 ×(1)

=>DIST. TRAVELLED IN 1 ROUND =>94.2m

SIMILARLY,

=>DIST. TRAVELLED IN 1.5 ROUND=(2πR×1.5)M

=>DIST. TRAVELLED IN 2 ROUND =(2πR×2)M

=>DIST. TRAVELLED IN 2.5 ROUND=(2πR×2.5)M

NOW,DISPLACEMENT

DISPLACEMENT=O

IT IS BEACAUSE WHEN THE INITIAL AND FINAL POSITION OF THE PATH ON WHICH WE TRAVELLED ARE STILL SAME , THEN THERE IS THE DISPLACEMENT BETWEEN INITIAL AND FINAL POSTION IS NOTHING OR WE SAY 0.