a particle is moving in horizontal circle at a height h from the vertex in a conical funnel with uniform speed.find its speed?
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the speed of the particle moving in the circular motion is √10h
Let the radius of the circle be r, mass m, velocity v, and let N be the force experienced by the particle
The vertical component of N should be equal to the weight
=> Nsin∅ = mg...................eq 1
The horizontal component of N should be equal to the centripetal force, i.e.
Ncos∅ = mv²/r...................eq 2
Dividing eq 1 by eq 2 we get,
tan∅ = gr/v²
But in the cone ,
tan∅ = r/h
Hence,
r/h = gr/v²
=> v² = gh
=> v = √gh = √10h (taking g = 10)
Hence the speed of the particle is √10h
sarath10112:
but how come tan angle in funnel is r/h
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