Question

A particle is moving in positive y axis (having magnitude 10 units). A force 2i+6j acts on it. Find the workdone.

Answer 1

Answer :

Work done = Force * displacement

W = f.s

| s | = 10 units

For Force, f

| f | = $\mathsf{\sqrt{{2}^{2}\:+\:{6}^{2}}}$

| f | = $\mathsf{\sqrt{4\: +\: 36}}$

| f | = $\mathsf{\sqrt{40}}$

| f | = 2 $\mathsf{\sqrt{10}}$ units.

Now, W = 2 $\mathsf{\sqrt{10}}$ × 10

=> W = 20$\mathsf{\sqrt{10}}$ N unit.