a particle is moving in sand under acceleration a=g-lamda×y², where lamda is a positive constant and y is the distance traveled in the y-axis.if the initial velocity is vnot and after traveling a distance ym,the particle stops,find lamda (the motion is along the y-axis)
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Answer:
The time period of oscillation is
Explanation:
Given that,
The acceleration a = -bx...(I)
Where, x = displacement
We know that,
The general formula of the acceleration
....(II)
Where, a = acceleration
x = displacement
=angular velocity
On comparing the both equation of acceleration
The time period of oscillation is
Put the value of
Hence, The time period of oscillation is
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