Question

a particle is moving in sand under acceleration a=g-lamda×y², where lamda is a positive constant and y is the distance traveled in the y-axis.if the initial velocity is vnot and after traveling a distance ym,the particle stops,find lamda (the motion is along the y-axis)
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Answer 1

Answer:

ANSWER

Velocity when t=2s is v2=10+2×4=18m/s

Velocity when t=5s is v5=10+2×25=60m/s

so change in velocity will be Δv=60−18=42m/s

time taken is Δt=5−2=3s

so the average acceleration will be a=ΔtΔv=3s42m/s=14m/s2