Question

A particle is moving in straight line such tha its displacement x =3—4t+5t^2 related to time the correct vt graph is

Answer 1

Answer:

Explanation:

A particle is moving in straight line such tha its displacement x =3—4t+5t^2 related to time the correct vt graph is

Displacement = 3 - 4t + 5t²

Velocity = Displacement / time

=> V = d (D)/dt

=> V = d(3 - 4t + 5t²)/dt

=> V = -4 + 10t

=> V = 10t - 4

time Velocity

0 -4

1 6

2 16

3 26

4 36

5 46

6 56

7 66

8 76