Question

a particle is moving in straight line with retardation of 2 m/s2 if initial velocity of particle is 11 m/s the displacement of particle between 0-2 sec is

Answer 1

Initial velocity,u=2 m/s.

Retardation=-1 m/s^2

Displacement in 1 sec is s1=ut+(1/2)at^2

s1=(2)(1)-(1/2)(1)(1)2=3/2 m

Displacement in 4 s is s4= (2)(4)-(1/2)(1)(16)=0

So, displacement=0–3/2=-3/2m

For distance: v=u-at=2-(1)t=0. Therefore,

at t=2s the displacement is maximum.

Sm=(2)(2)-(1/2)(1)(4)=2m

The total distance is 2sm-s1=(4)-(3/2)=2.5 m.