Question

a particle is moving in stright line 50 m in 4 sec and 60m in 7 sec find the initial velocity and constant acceleration

Answer 1

Answer:

Initial velocity will be 17.7391 m/sec

Constant acceleration will be -2.619 $m/sec^2$

Explanation:

We have given that the particle moves 50 m in 4 sec in straight line and then 60 m in 7 sec

According to second equation of motion we know that $s=ut+\frac{1}{2}at^2$

For first motion

$50=u\times 4+\frac{1}{2}\times a\times 4^2$

$4u+8a=50$----------------eqn 1

For second motion

$60=u\times 7+\frac{1}{2}\times a\times 7^2$

$7u+24.5a=60$-------------eqn 2

On solving eqn 1 and eqn 2

u = 17.7381 m/sec

And a = $-2.619m/sec^2$