Question

a particle is moving in such a way that its displacement at time t is give

Answer 1

Answer:

Step-by-step explanation:

For a particle moving in a straight line, the displacement of the particle at time t , is given by s=t3−6t2+3t+7. What is the velocity of the particle when its acceleration is zero?

s=t³-6t²+3t+7

Let the velocity of the particles be V.

Velocity(V) = ds/dt

∴ V= ds/dt = 3t²-12t+3

Hence,the acceleration of the particles will be :

a = dv/dt

a = 6t-12

But, a = 0

It follows that :

6t-12=0

∴ 6t = 12

∴ t = 2s

Therefore,

V = 3(2)² - 12(2) + 3,when t= 2s

V = 12 - 24 + 3

V = -9m/s

V = 9m/s

Answer 2

S=ut+1/2at^2
s=displacement covered
u=initial velocity
t=time taken
a=acceleration