Question

a particle is moving in x-y plane at 2m/s along x axis, 2 seconds later, its velocity is 4m/s in a direction making 60° with positive x axis. its average acceleration for this period of motion is​

Answer 1

Answer:

Explanation:

=> The acceleration of the particle can be represented into its horizontal as well as vertical component.

a = a_x i^ + a_y j^

a_x = 1.5 cos 37° = 1.2 m / s².

a_y = 1.5 sin 37° = 0.9 m / s²

=> Initial velocity of the particle is 8i^

=> The particle has no initial velocity in the positive direction of the y axis.

x = 8 * 4 + 1/2 * 1.2 * 4² = 32 + 9.6 = 41.6

y = 0 + 1/2 * 0.9 * 4² = 7.2

v_x (t = 4) = 8 + 1.2 * 4 = 12.8 m/s

v_y (t = 4) = 0 + 0.9 * 4 = 3.6 m/s

v = √v_x² + v_y²

= √12.8² + 3.6²

= 13.3 m/s

Thus, average acceleration of particle for this period of motion is​ 13.3 m/s.