a particle is moving in x-y plane at 2m/s along x axis, 2 seconds later, its velocity is 4m/s in a direction making 60° with positive x axis. its average acceleration for this period of motion is
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Answer:
Explanation:
=> The acceleration of the particle can be represented into its horizontal as well as vertical component.
a = a_x i^ + a_y j^
a_x = 1.5 cos 37° = 1.2 m / s².
a_y = 1.5 sin 37° = 0.9 m / s²
=> Initial velocity of the particle is 8i^
=> The particle has no initial velocity in the positive direction of the y axis.
x = 8 * 4 + 1/2 * 1.2 * 4² = 32 + 9.6 = 41.6
y = 0 + 1/2 * 0.9 * 4² = 7.2
v_x (t = 4) = 8 + 1.2 * 4 = 12.8 m/s
v_y (t = 4) = 0 + 0.9 * 4 = 3.6 m/s
v = √v_x² + v_y²
= √12.8² + 3.6²
= 13.3 m/s
Thus, average acceleration of particle for this period of motion is 13.3 m/s.
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