Question

A particle is moving on a circular path of 7 cm radius. Find its distance and displacement after three
revolutions
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Answer 1

Answer:-

Distance covered =442=22 cm. Displacement is the length of straight line AB i.e., the diameter of the circle. Hence displacement is 2×7 = 14 cm from A to B (AB)−→−−.

Explanation:-

Circumference of the circular path

= 2πr=2×227×7=44 cm.

When it covers half the circumference the particle moves from A to B along the path ACB .

Hence distance covered =442=22 cm. Displacement is the length of straight line AB i.e., the diameter of the circle. Hence displacement is 2×7 = 14 cm from A to B (AB)−→−−.

(ii) On completion of the total circular path ACBA, the distance covered is equal to the circumference of the circle = 44 cm.

As the particle comes back to its initial position displacement is zero.

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Answer 2

Answer:

Displacement is Zero

Distance is 132cm or 1.32m

Explanation:

Radius =7 cm

Displacement is zero because it is depend upon final and initial point.

Distance = 2πr × 3

2 ×22/7 × 7 ×3 = 66 × 2 = 132cm or 1.32m