Question

A particle is moving on a circular path of constant speed v and it moves between 2 points a and b which subtends an angle 60 degree at the centre of circle the magnitude of change on its velocity and change in magnitude of its velocity during motion from a to b are respectively

Answer 1

Change in velocity=

vcos(60)i+vsin(60)j-(vsin(60)j-vcos(60)i)=

2vcos(60)i

Change in momentum=2mvcos(60)i

Answer 2

Answer:

v,0

Explanation:

Since the body is moving with constant velocity, it is undergoing uniform circular motion. in uniform circular motion, there is no change in velocity. so change in magnitude of velocity is 0. There is only change in direction.

let the body be moving in anticlockwise direction from a to b

so velocity at b will be v sin 60 j and velocity at a will be -v cos 60 i

change in velocity vector =-v cos 60 i - v sin 60 j

magnitude of the above vector= v

final ans: v, 0

pls mark my answer as brainliest if it helps you............