a particle is moving on a circular path of radius 1 with an angular speed 2t²+1 find the angle between total acceleration and normal acceleration at t=1s
Answers
Answered by
0
Answer:
Solution
verified
Verified by Toppr
Radial acceleration a
n
=v
2
/r
at t = 1s, v= 2 m/s a
n
=2
2
/1=4m/s
2
Tangential acceleration a
t
=dv/dt=4t
at t = 1 s, a
t
=4m/s
2
so, a=
a
n
2
+a
t
2
a=
4
2
+4
2
=4
2
m/s
Answered by
0
Answer:
Radial acceleration a
n
=v
2
/r
at t = 1s, v= 2 m/s a
n
=2
2
/1=4m/s
2
Tangential acceleration a
t
=dv/dt=4t
at t = 1 s, a
t
=4m/s
2
so, a=
a
n
2
+a
t
2
a=
4
2
+4
2
=4
2
m/s
2
Solve any question of Motion in a Plane with:
Similar questions