A particle is moving on a circular path of radius 5 m
with uniform speed 10 ms from point A to B. The
magnitude of average velocity of particle in moving
from A to B is
Answers
Answered by
0
Answer:
Centripetal accl. is equal to v^2/r
ac = 5^2/5 = 5m/s^2.
Tangential accl.(at) is equal to
Change in velocity/ time taken.
Change in velocity = 5-(-5) =10.
Time period =( 2*pi. R) /V = 2*pi sec.
Time taken in half revolution is pi.
at = 10/pi.
Explanation:
Similar questions