Physics, asked by hrishikarelia, 3 months ago


A particle is moving on a circular path of radius m in such a way that magnitude of its velocit
100/√19
varies with time as v=2r +1. where v is velocity in m/s and t is time in s. The acceleration of the
particle at 1 = 2 s is
21 m's
9 m's
10 m's
13.5 m/s​

Answers

Answered by XxRedmanherexX
0

Answer:

13.5m/s

Explanation:

A particle is moving on a circular path of radius m in such a way that magnitude of its velocit 100/√19. varies with time as v=2r +1.

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