Question

A particle is moving on a straight line x + y = 2. Its angular momentum about origin is L = 3t + 2 (kg ms-). Find the force acting on the particle at t = 2 s. (x and y are in metre)​

Answer 1

The force acting on the particle is F = 3/√2 N

Explanation:

Angular momentum = Linear momentum x lever arm

Lever arm =  length of perpendicular online from origin = √2

3t + 2 = mv x √2

Differentiating both sides with respect to time.

3 = m dv/dt. √2

F = 3/√2 N

Thus the force acting on the particle is F = 3/√2 N

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