Question

A particle is moving on the x-axis such that its velocity varies with the x coordinate according to the
relation v= 2x +1. Find out the acceleration of the particle as a function of x.
(1) 2r-1 (2) 4x-1 (3) 4x +2 (4) None of these​

Answer 1

Answer ⇒ Option (c).  4x + 2.

Explanation ⇒ Given conditions,

v = 2x + 1

Differentiating both sides with respect to time,

dv/dt = 2(dx/dt) + 0

Since, dv/dt = a and dx/dt = v, we will get,

a = 2v

a = 2(2x + 1)

∴ a = 4x + 2

Thus, option (3). is correct.

Hope it helps.

Answer 2

Answer ⇒ Option (c).  4x + 2.

Explanation ⇒ Given conditions,

v = 2x + 1

Differentiating both sides with respect to time,

dv/dt = 2(dx/dt) + 0

Since, dv/dt = a and dx/dt = v, we will get,

a = 2v

a = 2(2x + 1)

∴ a = 4x + 2

Thus, option (3). is correct.