: A particle is moving rectilinearly with a time varying acceleration a = 4+2t, where a is in
m/s and t is in sec. If the particle is starting its motion with a velocity of –3 m/s from x =
0. Draw a-t, v-t and x-t curve for the particle.
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Answer:
a=4−2x
a=vdv/dx
vdv=(4−2x)dx
Integrating from x = 0 to x = x1 where particle will come to instantaneous rest again,
[v
2
/2]=[4x−x
2
]
0−0=4x
1
−x
1
2
x
1
=4m .
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