Physics, asked by bandita7, 11 months ago

A particle is moving such that its position
coordinates (x, y) are
(2 m, 3 m) at time t = 0,
(6 m, 7 m) at time t = 2 s and
(13 m, 14 m) at time t = 5 s.
is
Average velocity vector (Var) from t = 0 to t = 5 s
[AIPMT-2014]
(1) 3 (13ſ +141) (2) +
(3) 265 +i (4) 1 / 1 + 1)​

Answers

Answered by mohdkhalid01081999
5

Answer:11/5(i+j)

Explanation:

Answered by sarthak0504
29

Answer:

11/5i +11/5j=11/5(i+j)

Explanation:

average velocity =total displacement /total time

=(Sf-Si) i +(Sf-Si) j/total time

=(13-2)i+(14-3)j/5

=11/5i+11/5j

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