Question

A particle is moving towards East with a velocity 10m/sec In 10 seconds the velocity changes to 10m/sec Northwards The average acceleration during the period is
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Answer 1

Answer:

Final velocity Vf = 10j m/s

Initial velocity Vi = 10i m/s

Time taken T = 10s

Average acceleration a = (Vf-Vi)/T

a = (10j - 10i)/10 = (i - j) m/s^2

a = (i - j) m/s^2

|a| = ¬/2 m/s^2