Question

A particle is moving towards east with a
velocity of 5 ms-1. In 10 seconds the velocity
changes to 5 ms. northwards. The average
acceleration in this time is
(A) 5 ms-2 towards north-west
(B) 0
(C) ms 2 towards north
s-2 towards north-east
10. A force of 200 N is required to push on..
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Answer 1

Answer:

0 m/s

Explanation:

u= 5 m/s East

v= 5m/s North

t = 10sec

a = v-u ÷ t

v- u = 5 - 5

= 0 m/s

So, a = 0 ÷ 10

= 0 m/s^2