Question

. A particle is moving up an inclined plane. Its velocity changes from 15m/s to 10m/s in two

seconds. What is its acceleration?​

Answer 1

Answer:

we know acceleration=final velocity (v) _ intial velocity(u)/time (t)

Explanation:

a= v_u÷t

a= 10_15/2

a= _5/2

a= _2.5m/s squar

Answer 2

$\huge\mathtt\pink{A}\mathtt\red{N}\mathtt\blue{S}\mathtt\green{W}\mathtt\purple{E}\mathtt\green{R}$

Given:-

• initial velocity of particle= 15m/s
• Final velocity of particle= 10m/s
• Time of motion=2sec

To find:-

• acceleration

solution:-

$\large \\: \: \: \: \: \: \: \: \: \: \: \rightarrow \mathtt \red{formula \: = v = u + at}$

$\large \\: \: \: \: \: \: \: \rightarrow \mathtt \blue{put \: values \: in \: formula}$

$\large \\: \: \: \: \: \: \: \rightarrow \mathtt \green{10 = 15 + a \times 2}$

$\large \\: \: \: \: \: \: \: \rightarrow \mathtt \pink{ \boxed{a = - 2.5m {s}^{ - 2} }}$

Note:-

acceleration comes negative because objects velocity is decreased with time.