A particle is moving up on an inclined plane . it's velocity changes from 15m/s to 10m/s in two seconds. what is its acceleration ?
Answers
Answered by
17
Acceleration(a) =v-u/t
v=10 , u=15
= 10-15/2 =-2.5m/s^2
Therefore acceleration (a) =-2.5m/s^2
Hope it is correct.
v=10 , u=15
= 10-15/2 =-2.5m/s^2
Therefore acceleration (a) =-2.5m/s^2
Hope it is correct.
Sneha20011:
10/2 = 5 and 15-5=10
and the unit of acceleration is meter/second square
'U' is final velocity and 'v' is initial velocity but u took it opposite
'U' is final velocity and 'v' is initial velocity but u took it opposite
it's ok
...
ans : u = 15m/s. v= 10m/s. T= 2 s. . = v-u/t = 10-15/2 = -5/2 = -2.5m/s
this is the ans , I got it
you are correct.I substituted the values wrong
ok i will change
Answered by
7
v=u-at
a=u-v/t
u=15m/s
v=10m/s
t=2s
a=2.5m/s2
a=u-v/t
u=15m/s
v=10m/s
t=2s
a=2.5m/s2
tq
ans = -2.5m/s2
Similar questions