Question

A particle is moving with a uniform acceleration its position time t second is given in metres by the relation
x = 3+4 t +5t^2.calculate the magnitude of its uniform acceleration.​

Answer 1

Answer:

10 m/s^2

Explanation:

v=dx/dt = d(3+4 t +5t^2)/dt

= 10t + 4

a= dv/dt = 10 m/s^2

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