Question

A particle is moving with a velocity of 10m/s towards east. After 10s its velocity

Answer 1

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Answer 2

Given that,

Initial velocity of the particle, u = 10 m/s (due east)

Let us assume that after 10 s, its velocity is changes to 10 m/s  towards north, v = 10 m/s (north)

To find,

Its average acceleration

Solution,

Acceleration of a particle is given by the change in velocity per unit time. The change in velocity in this case is given by :

$v-u=\sqrt{10^+10^2} \\\\v-u=10\sqrt{2}$

Average acceleration becomes :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{10\sqrt{2} }{10}\\\\a=\sqrt{2} \ m/s^2$

So, the magnitude of average acceleration is $\sqrt{2} \ m/s^2$.

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Average acceleration

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