Physics, asked by Sofyverma, 1 year ago

A particle is moving with a velocity of v =(3+6t+9t^2)cm/s. Find out
1. The acceleration of the particle at t=3s
2. The displacement of the particle in the interval t=5s to t=8s.

Answers

Answered by kylar890

0

the answer is 9876543213456890

Answered by aadharshadhithya

1

Hope this Helps.........!!!

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Sofyverma: Thank you so much...

aadharshadhithya: No mention.

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