Question

a particle is moving with acceleration 4cos2t-8sin2t+6t find it's velocity given that velocity is zero at=0​

Answer 1

Explanation:

ANSWER

The displacement of the particle is in the form of

x=Asinωt+Bcosωt

The amplitude is given as

A=

3

2

+4

2

Hence the amplitude is given as5

The phase difference is of

2

π

The maximum speed is given as

v

max

=Aω

v

max

=5×2

Hence the maximum velocity is10

Answer 2

Answer:

The position vector of a particle is given by R(t) = (t, t2,t3). ... For the acceleration vector, we get . A = dV dt. = (0, 2, 6t). The velocity is 10