Question

a particle is moving with an initial velocity of 2 m/s and covers a distance of 20 m in 5 s. Find (a) acceleration of particle (b) time taken by the particle to attain a velocity of 10 m/s.​

Answer 1

ACCELERATION IS 0.8 m/s² AND TIME TAKEN IS 10 seconds.

Given:

• Initial velocity = 2 m/s
• Distance covered = 20 m
• Time taken is 5 sec

To find:

• Acceleration of body ?
• Time needed to attain 10 m/s?

Calculation:

Let the acceleration of the particle be 'a':

Applying equation of motion:

$s = ut + \dfrac{1}{2} a {t}^{2}$

$\implies \: 20 = 2(5) + \dfrac{1}{2} a {(5)}^{2}$

$\implies \: 20 =10 + \dfrac{25}{2}a$

$\implies \: \dfrac{25}{2}a = 10$

$\implies \: a = 0.8 \: m {s}^{ - 2}$

So, acceleration is 0.8 m/s².

Let time required be t :

$v = u + at$

$\implies \: 10 = 2 + (0.8)t$

$\implies \: 0.8t = 8$

$\implies t = 10 \: sec$

So, time needed is 10 seconds.