Question

A particle is moving with an initial velocity of 5ms^-¹. What will be the velocity of the particle at t=3s, of the acceleration of the particle is given by
a=16t³-12t²+6t-25​

Answer 1

Answer:

Given : u=5 m/s a=−2.5 m/s

2

t=4 s

Displacement S=ut+

2

1

at

2

∴ S=5×4+

2

1

(−2.5)(4)

2

=0 m

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Answer 2

Answer:

173 m/s

Explanation:

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