Question

A particle is moving with an initial velocityf 5m/s is subjected to a uniform acceleration of 2.5m/s.find it's velocity after 4secs?

Answer 1

Answer:

15 m/s

Explanation:

Given:

Initial velocity (u) = 5 m/s

Acceleration (a) = 2.5 m/s²

Time (t) = 4 seconds

To find:

Velocity after 4 seconds (v)

We can use the first equation of motion which is applicable for uniform motion which says:

V=u+at

Where:

v = final velocity

u = initial velocity

a = acceleration

t = time

Substituting the above values:

V = 5+2.5×4

V = 5 +10

V = 15 m/s

The velocity of the particle after 4 seconds is equal to 15 m/s

Answer 2

Given :-

Initial velocity (u)= 5m/s

Acceleration (a)= 2.5m/s^2

Time (t)=4seconds

To find

The final velocity of particle

• By first equation of motion

$\bigstar{\boxed{\textsf{\textbf{v=u+at}}}}$

Where ,

v --- Final velocity

u--- Initial velocity

a --- Acceleration

t --- Time

• Now find the final velocity

• put the given values

$\longmapsto\sf v=u+at\\ \\ \longmapsto\sf v= 5+2.5\times 4\\ \\ \longmapsto\sf v= 5+10\\ \\ \longmapsto\sf v= 15m/s$

$\underline{\textsf{\textbf{\dag\ \ Final \ velocity = 15m/s}}}$