Question

a particle is moving with an uniform acceleration. it's displacement at any instant 't' is given by , S = 10t + 4.9t² . what is
(i) initial velocity
(ii) velocity at t = 3 seconds
(iii) the uniform acceleration?



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Answer 1

s=10t+4.9t

2

...(1)

Acceleration is constant

From kinematics: s=ut+

2

1

at

2

..(2)

comparing (1) and (2)

i)initial velocity u=10m/s

ii)Acceleration,a=4.9×2=9.8m/s

2

iii)v

2

−u

2

=2as

s(t=3)=10×3+

2

1

×9.8×9

=30+44.1=74.1m

v

2

=u

2

+2as

=100+2×9.8×74.1=1552.36

velocity at t=3,v=39.4m/s

Answered By=shreyash. .......

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