Question

A particle is moving with constant acceleration from p
to Qin a straight line. A is the mid-point of PQ if u and
vare the speed at p and Q respectively. The speed at A
is​

Answer 1

Answer:

Let the distance between A and B=s and as mentioned C is the midpoint of A and B thus distance between A C and  

C B=  

2

s

​  

 

From equation of motion we get distance between AB  

v  

2

=u  

2

+2as

s=  

2a

v  

2

−u  

2

 

​  

----------(1)

Let speed of the vehicle be pm/s at point C

Again from equation of motion we get,

p  

2

=u  

2

+2a  

2

s

​  

 

as distance between A and C is  

2

s

​  

 

s=  

a

p  

2

−u  

2

 

​  

-------(2)  

Computing 1 and 2 we get

a

p  

2

−u  

2

 

​  

=  

2a

v  

2

−u  

2

 

​  

 

p  

2

=  

2

v  

2

+u  

2

hope it helps(sorry for errors)