Question

A particle is moving with constant speed in a circular path. The ratio of average velocity
to its instantaneous velocity when the particle describes an angle
theta=π/2
is2√x/π
then the value of x is​

Answer 1

Answer:

[tex\] x=2[/tex]

Explanation:

1) Let the speed of particle be $v$ and radius  of circular path be

'r' .

When particle describes an angle , $\theta=\frac{\pi}{2}$.

Displacement , is given by

$\sqrt{r^2+r^2}=\sqrt{2}r$

2) Now,

Average Velocity = Total Displacement / Total time

   Total Displacement =$r\sqrt{2}$

Total time = $\frac{\pi*r/2}{v}=\frac{\pi*r}{2v}$

Now,

$v_{avg}=\frac{r\sqrt{2}}{\frac{\pi*r}{2v}}=\frac{2\sqrt{2}v}{\pi}$

Hence, the required ratio is given by

$\frac{2\sqrt{2}v}{\pi*v}=\frac{2\sqrt{2}}{\pi}$

Hence, the value of x=2.

Answer 2

Answer:

hope you UNDERSTOOD this answer