A particle is moving with constant speed over circle x2 + y2 = 50, with speed vums
V10 m/s.
Acceleration of the particle, when it is at point (5.5) is (in m/s)
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Explanation:
it contains only centripetal acceleration
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Given:
Speed(v)= 10 m/s (constant)
Equation of a circle is, x²+y²=50⇒ r² = 50⇒ r = 5√2
Acceleration(a)= ?
To find the acceleration of the particle, when it is at point (5.5)
Solution:
Acceleration (a) is calculated as,
=10²/5√2
=100/5√2
=20/√2 m/s
=14.14 m/s
Hence, acceleration of the particle, when it is at point (5.5) is 14.14 m/s².
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