Question

A particle is moving with initial 10 m/s
it retardation 2 m/s squre constant calculate 1. displacement in 6 second
2. distance in 6 second​

Answer 1

Explanation:

Given,

u=10m/s

a=−2m/s

n=5The distance covered by the particle nth sec

sn

=u+

2

a

(2n−1)

S

5

=10+

2

−2

(2×5−1)

S

5

=10−9

S

5

=1m

Answer 2

Answer:

chimkandi giri is the answer

Explanation: