A particle is moving with initial 10 m/s
it retardation 2 m/s squre constant calculate 1. displacement in 6 second
2. distance in 6 second
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0
Explanation:
Given,
u=10m/s
a=−2m/s
n=5The distance covered by the particle nth sec
sn
=u+
2
a
(2n−1)
S
5
=10+
2
−2
(2×5−1)
S
5
=10−9
S
5
=1m
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Answer:
chimkandi giri is the answer
Explanation:
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