Question

a particle is moving with speed 6m/s along the direction of A=2i+2j-k , then it's velocity is​

Answer 1

Step-by-step explanation:

v = |v|/v(unit vector)

A = 2i +2j -k

|A|= √4+4+1

= 3

Unit vector = (2i +2j -k)/3

And velocity will be equal to=>

(2i +2j -k)× 1/3 × 6

4i +4j -2k

Hope it helps uh

Answer 2

The velocity is $(4 i + 4j -2k) m/s$.

Step-by-step explanation:

Given:

Speed $=6m/s$

Direction $A=2i+2j-k$.

To find:

To find the velocity.

Formula used:

Velocity = speed.

Solution:

$\[ \vec{ v } ={6.\frac{\[ \vec{ A } \\~\\}\[ \vec{ |A| } \\~\\}$

$\[ \vec{ v } ={6\times \frac{\[ \vec{ 2i+2j-k } \\~\\}\[ \vec{ \sqrt{4+4+1} } \\~\\}$

$\[ \vec{ v } = (4 i + 4j -2k) m/s$

Hence, the velocity is $4 i + 4j -2k m/s$.

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