A particle is moving with speed v in a straight line. If the particle start decelerating with an acceleration a and then it achieved same speed after the time
(1) 
(2) 
(3) 
(4)
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Answered by
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Dear Student,
◆ Answer -
(1) 2v/a
● Explanation -
When particle starts decelerating,
v' = v - at
At a point when velocity will be zero,
0 = v - at
t = v/a
Then the particle will go in negative direction starting from rest,
v" = v' - at'
-v = 0 - at'
t' = v/a
Therefore, total time taken will be -
T = t + t'
T = v/a + v/a
T = 2v/a
Therefore, particle will again achieve same speed after time 2v/a.
Best luck dear...
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