A particle is moving with the velocity speed of 20 m per second in a circular path of radius 14 m . The magnitude of average acceleration of the particle between two diametrically opposite point is
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It means,distance between two points is 24m
acceleration=velocity/time
as time =distance /speed
then time is equal to 6/5 seconds.
acceleration=20by6/5
then acceleration is equal to 13.4ms^2.
I think so my answer is correct.
acceleration=velocity/time
as time =distance /speed
then time is equal to 6/5 seconds.
acceleration=20by6/5
then acceleration is equal to 13.4ms^2.
I think so my answer is correct.
gellisurabhi:
if my answer is correct mark me brainlest
option are. a) 100/11 b)200/11 c)400/11 d) zero
your answer is not in options
opitions are in m or in cm
m/ s^2
acceleration
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