Question

A particle is moving with uniform acceleration along a straight line ABC. Its velocity at ‘A’ and ‘B’ are 6 m/s and 9 m/s respectively. If AB: BC = 5: 16 then its velocity at ‘C’ is​

Answer 1

Explanation:

What would you like to ask?

11th

Physics

Motion in a Straight Line

Problems on Equation of Motion

A particle is moving with u...

PHYSICS

A particle is moving with uniform acceleration along a straight line ABC. Its velocity at 'A' and 'B' are 6m/s and 9m/s respectively. AB:BC=5:16 then its velocity at 'C' is

HARD

Share

Study later

CALCULATOR

Enter the know values to find unknown

Acceleration

Distance

Final Velocity

v = u + a*t

Initial Velocity u

m/s

Final Velocity v

m/s

Time t

s

Acceleration a

m/s²

RESET VALUES

ANSWER

Given:

The velocity of particle at point A, V

A

=6m/s

The velocity of particle at point B, V

B

=9m/s

Acceleration of the particle is uniform

Ratio of distance between AB and BC, AB:BC=5:16

To find:

The velocity of particle at C

Consider that the distance between A and B is 5x and between B and C is 16x as they in ratio of 5:16

For motion between A→B:

Using third equation motion : v

2

=u

2

+2as

final velocity is V

B

and initial is V

A

and displacement is 5x

(9)

2

=(6)

2

+2a(5x)

81=36+10ax

ax=

10

45

=4.5

For motion between B→C

v

2

=u

2

+2as

2

v

2

=(9)

2

+2a(16x)

v

2

=(81)+32ax

substitute 4.5 for ax

v

2

=81+32(4.5)

=225

v=

225

=15 m/s