A particle is moving with uniform acceleration ; in the 8th second and 13th second of its motion it describes 255 and 225 cm. Find the initial velocity and acceleration
Answers
Answer:
u= 300cm/s. a= - 6 cm/s²
Explanation:
Ask Questions, Get Answers
Questions >> Extras >> Student Questions
Next similar questionQ)
A particle is moving with uniform acceleration, in eighth and thirteenth se
A particle is moving with uniform acceleration, in eighth and thirteenth second after starting it moves through 255cm and 225cm respectively.
Homework help Donate
A)
Here we have the distance traveled In 8th and 13th sec, And we know the formula for particular Time distance, or distance for nth sec That is -. S for nth sec = u+1/2a(2n-1) So by putting the information on this formula We got the ans.... Let solve... We have ,. u=? And. a=? Distance in 8th sec= u + 1/2 a(2×8-1) = u +1/2×15a..............(1) Distance in 13th sec=u +1/2×(2×13-1)a =u +1/2×25a .............(2) Now I'm substracting 1 from 2 we have 225-255 =1/2×10 a We have a =-6 cm/ sec² Now on putting the value of a in any of the equation You got the value of u = 300cm/ s