Question

A particle is moving with uniform speed along a circle of radius 20cm. If angular
velocity of particle is 5 rad s-¹ then its speed is


1) 25ms-¹
2) 5ms-¹
3) 1ms-¹
4) 0.2 ms-1

​

Answer 1

Answer:

Since speed increases uniformly , average tangential acceleration is equal to instantaneous tangential acceleration is given .

a

t

=

dt

dv

=

t

2

−t

1

v

2

−v

1

2.0

60−5.0

ms

−2

=0.5ms)

2

The angular acceleration is α =a

t

/r

20cm

0.5ms

−2

=2.5rads

−2

Explanation:

please Mark as brilliant

Answer 2

Explanation:

We have,,

Radius of the circle,r = 20 cm

Now,,

Angular velocity,$\sf{v_{\Theta}=5 \:rad{s^{-1}}}$

Therefore,, speed = v = length of arc which subtends an angle of 5 rad (l) / sec

length of arc,l = r∅ = 20 × 5 = 100 cm

$\implies{\sf{v={l}s^{-1}}}$

$\implies{\sf{v=100 cms^{-1}}}$

$\implies{\boxed{\sf{v=1 ms^{-1}}}}$

Therefore, the third (3) option is correct.

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