Question

a particle is moving with velocity 5m/stowards east and it's velocity changes to 5m/s north in 10 seconds find the acceleration​

Answer 1

Answer:

acceleration vector=1/2j-1/2i

Magnitude of acceleration=√2/2

Explanation:

Considering east as positive x axis and north as positive y Axis

Initial velocity vector(u)=5i

Final velocity vector (v)=5j

change in velocity=v-u=5j-5i

acceleration = change in velocity/time

acceleration = (5j- 5i)/10

acceleration=(5j/10 ) - (5i/10)

acceleration=(i/2 )-(j/2)

Magnitude=√{(1/2)²+(1/2)²}

Magnitude=√2/2