Physics, asked by MiniDoraemon, 8 months ago

A particle is moving with velocity v = k(yi +xj) ,where k is a constant . the general equation for its path is [AIEEE:2010]​

Answers

Answered by TheLifeRacer
7

Given :- V = kyi+ kx j

  • dx/dt = ky
  • dy/dt = kx
  • dy/dx = dy/dt ×dt/dx = kx/ky
  • ydy =xdx

Integration and using , ∫Xⁿdx = Xⁿ⁺¹/n+1, we have

  • ∫ydy =∫ xdx
  • y²/2 = x²/2
  • y²=x²
  • y² = x²+c Is general equation for its path
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